Question

Sandy mixed together 3 gallons of one brand of juice and 2 gallons of a second brand of juice, which contains 60 percent real fruit juice. Find the percent of real fruit juice in the first brand if the mixture contained 30 percent real fruit juice. Which of the following equations could be used to solve this?

Answer 1

Answer:

Let the percent of the real fruit in the first

brand = x

Given that number of gallons of real fruit

in the first brand = 9 gallons

Given that percent of the real fruit in the

second brand = 48%

Given that number of gallons of real fruit

in the second brand = 8 gallons

Given that percent of the real fruit in the

mixture = 30%

then number of gallons of real fruit in the

mixture = (9+8) = 17 gallons

Then we get equation:

[x% of 9 gallons] + [48% of 8 gallons] =

[30% of 17 gallons]

9x+48(8)=30(17)

9x+3845510

9x=510-384

9x=126

x=126/9

x=14

Plz mark it as brainlist answer