sanganabasava rides a bicycle from his home to ashrama. He covers 125 m at the end of first minute. 135 m at the end of second minute and so on. If he reaches the ashram at the end of 10 min. Find the distance between his home and ashram. *
1 point
a) 1.5km
b) 1.7 km
c) 2 km
d) 2.5 km
Answers
Given : sanganabasava rides a bicycle from his home to ashrama. He covers 125 m at the end of first minute. 135 m at the end of second minute and so on. he reaches the ashram at the end of 10 min
To find : the distance between his home and ashram
Solution:
Forms an AP with d = 10 m & a = 125 m
1st Min distance = 125 m
2nd Min Distance = 135 m
3rd Min Distance = 145 m
10Min Distance = 215 m ( 125 + (10 - 1)10)
Sum of an AP = (n/2)(a + Last term)
Total Distance = (10/2)(125 + 215)
= 5 ( 340)
= 1700 m
= 1.7 km
distance between his home and ashram = 1.7 km
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