Math, asked by Sharad9834, 10 months ago

Sangeetha borrows ₹50,000 at the rate of 6% p.a. After 2 years, she borrows ₹75,000 at the rate of 9% p.a., and after 3 years she borrows ₹25,000 at the rate of 14% per annum. What is the total simple interest that she has paid at the end of 9 years?

Answers

Answered by kanishk123
2

Answer:

it's so simpleee......

CASE I

Principle = $50000

Rate = 6% p.a.

Time = 1 year {as not mentioned}

S.I = PRT = 50000×6×1 = $3000

100 100

CASE II

Principle = $75000

Rate = 9% p.a.

Time = 2 years

S.I = PRT = 75000×9×2 = $13500

100 100

CASE III

Principle = $25000

Rate = 14% p.a.

Time = 9 years

S.I. = PRT = 25000×14×9 = $31500

100 100

TOTAL S.I. SHE PAID AT THE END OF 9 YEARS IS

${3000+31500+13500} = $ 48000.

AND AMOUNT WILL BE......

(50000+3000)+(75000+13500)+(25000+31500) = $198000

MARK AS BRAINLIEST!!

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