Sanjay is now 1 by 2 as old as his brother in 6 more years he will be 3 by 5 as old as his brother's then what is the present age of each boy
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let the brothers age be x ,then sanjays age is x/2
given that after six years brothers age will be (x+6) and sanjays age will be [3(x+6)]/5 but according to the question it is also so that sanjays age after six years is x/2+6=(x+12)/2
so ATP... [3(x+6)]/5=(x+12)/2=>2*3(x+6)=5(x+12) =>6(x+6)=5(x+12)=>6x+36=5x+60 =>6x-5x=60-36=>x=24
SO ACCORDING TO THE PROBLEM THE BROTHER'S AGE IS 24 AND SANJAY'S AGE (1/2 of x=24/2=12) IS 12
HOPE IT HELPS
given that after six years brothers age will be (x+6) and sanjays age will be [3(x+6)]/5 but according to the question it is also so that sanjays age after six years is x/2+6=(x+12)/2
so ATP... [3(x+6)]/5=(x+12)/2=>2*3(x+6)=5(x+12) =>6(x+6)=5(x+12)=>6x+36=5x+60 =>6x-5x=60-36=>x=24
SO ACCORDING TO THE PROBLEM THE BROTHER'S AGE IS 24 AND SANJAY'S AGE (1/2 of x=24/2=12) IS 12
HOPE IT HELPS
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