Question

Sanjay is now half as old as his brother. In 6 more years he will be 3/5 as old as his brother then.What is their present ages?

Please answer ASAP​

Answer 1

Answer:

Sanjay's present age = 12 years,

His brother's present age = 24 years

Step-by-step explanation:

Let his brother's age be x

then Sanjay's age be 1/2x

After 6 years,

Sanjay's age be 1/2x+6

And his brother's age be x+6

ATQ,

x+6 = 3/5 (1/2x+6)

3/5(x+6) = 1/2x+6

3/5x + 18/5 = 1/2 x + 6

3/5 x - 1/2 x = 6 - 18/5

(6x - 5x )/ 10 = (30 - 18) / 5

x / 10 = 12/5

x = (12/5)× 10

x = 24

Therefore, his brother's present age is 24 years whereas Sanjay's age is 1/2 of x (which is 1/2 of 24 years) = 12 years.

Answer 2

Answer:

present age of sanjay = 12 years

present age of his brother = 24 years

Step-by-step explanation:

Let Sanjay's present age be x

and hus brother's present age be y

From question,

$x \: = \frac{y}{2} - - - - - - (1)$

After 6 years,

Sanjay's age = x + 6

Brother's age = y + 6

From question,

$x \: + 6 = \frac{3}{5} (y + 6) \\ 5x + 30 = 3y + 18$

putting value from equation (1),

$5( \frac{y}{2} ) + 30 = 3y + 18 \\ 3y - ( \frac{5}{2} )y = 30 - 18 \\ \frac{1}{2} y = 12 \\ y = 24 \\ from \: equation(1) \\ x = 12$