Math, asked by phalit69, 1 year ago

Sanjay is now one by two as old as his brother in 6 more years he will be 3 by 5 years old his brother then what is the present age of each boy

Answers

Answered by BrainlyFIRE
11
hiii mate

Let's take Sanjay's present age to be 'x'. That way, his brother's present age shall be '2x'.

Now, 6 years from now, Sanjay's age can be denoted as 'x + 6′ and brother's age as '2x + 6′.

According to the question,

x + 6 = 3/5 (2x + 6)

→5 (x + 6) = 3 (2x + 6)

5x + 30 = 6x + 18

30–18 = 6x - 5x

x = 12

Therefore, Sanjay's present age is 12 years and his brother's age is twice his age, i.e., 24 years.

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