Sanjay is now one by two as old as his brother in 6 more years he will be 3 by 5 years old his brother then what is the present age of each boy
Answers
Answered by
11
hiii mate
Let's take Sanjay's present age to be 'x'. That way, his brother's present age shall be '2x'.
Now, 6 years from now, Sanjay's age can be denoted as 'x + 6′ and brother's age as '2x + 6′.
According to the question,
x + 6 = 3/5 (2x + 6)
→5 (x + 6) = 3 (2x + 6)
5x + 30 = 6x + 18
30–18 = 6x - 5x
x = 12
Therefore, Sanjay's present age is 12 years and his brother's age is twice his age, i.e., 24 years.
Let's take Sanjay's present age to be 'x'. That way, his brother's present age shall be '2x'.
Now, 6 years from now, Sanjay's age can be denoted as 'x + 6′ and brother's age as '2x + 6′.
According to the question,
x + 6 = 3/5 (2x + 6)
→5 (x + 6) = 3 (2x + 6)
5x + 30 = 6x + 18
30–18 = 6x - 5x
x = 12
Therefore, Sanjay's present age is 12 years and his brother's age is twice his age, i.e., 24 years.
Similar questions
Math,
7 months ago
Computer Science,
7 months ago
Math,
7 months ago
English,
1 year ago
Math,
1 year ago