sanjay seved Rs.5 in the first week of a year and then increased his weekly savings by Rs.1.75.if in the nth week his weekly seving was Rs.20.75,find n.
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the saving value increases by 1.75
the series of investment is in an AP
with common difference (d) =1.75&a=5
we know that,
TN =a+(n-1)d
20.75 =5+(n-1)1.75
n =10
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Answer:
Step-by-step explanation:
the saving value increases by 1.75
the series of investment is in an AP
with common difference (d) =1.75&a=5
we know that,
AN =a+(n-1)d
20.75 =5+(n-1)1.75
n =10
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