Question

Sanjeev secured 438 marks out of 900 and failed by 12 marks find the minimum number of marks required the pass examination also find minimum percent marks

Answer 1

Sanjev secured 438 and gone fail from 12 so the minimum passing marks is 438+12 = 450 and as u can see this is the half of900 so the minimum passing marks persentage is 50/

Answer 2

heya frnd!

here's ur answer...

given that Sanjeev secured 438marks out of 900 and failed by 12marks.

so the minimum number of marks required to pass is=438+12

=450marks

therefore percentage of minimum marks required to pass=450/900×100

=450/9

=50%

hope this helps u..!

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