Question

Sanjiv has rupees 60 in 1o rupee and 5 rupee coins. If the 10 rupee coins exceed the number of 5 rupee coins by three , how many coins of each does he have ?

Answer 1

x=5,y=2 you will get by solving above equations

Answer 2

Answer:

10 rupees coin are 5 and 5 rupee coin are 2.

Step-by-step explanation:

Given : Sanjiv has rupees 60 in 10 rupee and 5 rupee coins. If the 10 rupee coins exceed the number of 5 rupee coins by three.

To find : How many coins of each does he have ?

Solution :

Let the number of 10 rupees coin be 'x'

and 5 rupees coin be' y'

According to question,

$10x + 5y = 60$ .....(1)

and number of 10 rupees coins are 3 more than 5 rupees coins  

So,  $10(y+3) + 5y =60$

$10y+30 + 5y =60$

$15y=30$

$y=2$

Substitute in (1)

$10x + 5(2) = 60$

$10x + 10= 60$

$10x=50$

$x=5$

Therefore, 10 rupees coin are 5 and 5 rupee coin are 2.