Sanket purchased a rectangular plot having area 200 m square length of the plot was 10m more than its breadth find the length and breadth of the plot
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6
area of rectangle equal to length X breadth equal to 200 m square
length is given 10 + breath
so the equation will be 10 plus breath into breadth
this is B equals to 10 +breadth square
10+b^2=200
b^2=200-10
b^2=190
b=√190
length is equal to 10 + under root 190
length is given 10 + breath
so the equation will be 10 plus breath into breadth
this is B equals to 10 +breadth square
10+b^2=200
b^2=200-10
b^2=190
b=√190
length is equal to 10 + under root 190
Answered by
39
Acc to the question, area of the rectangular plot = 200 sqm.
i.e. L x B = 200 sqm.
As per condition, L = B + 10.
Putting the value of L we get,
(B + 10) x B = 200 sqm.
or, + 10B = 200
or, + 10B - 200 = 0
or, + 20B - 10B - 200 = 0
or, B(B + 20) - 10(B + 20) = 0.
or, (B - 10) (B + 20) = 0
Since breadth cannot be negative so, B = 10m.
Therefore L = B + 10 = 10 + 10 = 20m (Ans)
Thus length = 20m, breadth = 10m.
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