Question

sanskrit bhasha ka mahtva in sanskrit

Answer 1

Explanation:

we have to find the magnitude of displacement of the particle which is moving from A to B.

solution : this question can be solved by many methods. but the most easiest method for this type of question is vector method.

we assume, horizontal line as x - axis and vertical line as y - axis

so, horizontal line denotes i (unit vector) and vertical line denotes j with sign.

particle starts to move from A and moves 70 m along positive direction of x - axis.

so, in vector form, s₁ = 70i

then moves 65 m along negative direction of y - axis

so, s₂ = -65 j

similarly, s₃ = -32i , s₄ = -13j , s₅ = -95i , s₆ = +44j

s_7s

7

= 30i , s_8s

8

= 60j , s_9s

9

= 27i , s₁₀ = -9j , s₁₁ = 15i , s₁₂ = 3j

now displacement of particle from A to B = s_1+s_2+s_3+s_4+s_5+s_6+s_7+s_8+s_9+s_{10}+s_{11}+s_