Question

Santosh, a physical education teacher, arranged three groups of 140, 91 and 63 students for the ​march past. If he arranged the same number of students in each ​row, find the number of students he arranged in each row?

Answer 1

Step-by-step explanation:

physical education teacher arranged three groups 140 , 91 ,and 63 students for the march past.

And

He arranged the same number of students in each rows .

So, We find HCF of ( 140 , 91 and 63 ) 

140 = 2 × 2 × 5 × 7

And

91 = 7  × 13

And

63  = 3 × 3 × 7 

So,

HCF of ( 140 , 91 and 63 )   = 7 

Then we can say

The number of students he arranged in each row = 7( Ans )

Answer 2

Answer:

Step-by-step explanation:

As we have to find the number of students in each row, we should find the HCF or the highest common factor.

We will use the method of listing down factors.

140- 1, 2, 4, 5, 7, 10, 14, 20, 28, 35, 70, 140

91- 1, 7, 13, 91

63- 1,3,7,9,21,63

As we see that 7 in the highest common factor, the HCF of 140,91 and 63 is 7.

Ans: Santosh arranged 7 children in each row.