Math, asked by Anuragdeep, 7 months ago

· Santosh borrowed 10,000 from Suman at 12% p.a. for 3 years at simple interest. He lent it further to Narayan
at 20% p.a. compounded half-yearly for three years. How much did he earn in this transaction?​

Answers

Answered by ani2050
2

Step-by-step explanation:

BORROW

P =1000

r = 12%

T =3yrs

I=PTr/100=10000×3×12/100=3600

.

LENT

P=10000

T=3yrs

r=20%=10%+10%(Half yearly)

I=?

.

10000---------10%

1st yr-(1000+1000)

2nd yr-(1000+1000)+100+100(1000×10% half yearly)

3rd yr-(1000+1000)+100+100+100+100+10+10(10% of 100)

So.Total CI = 6000+600+20=6620

.

Total earnings = Get-Give=6620-3600=3020*

Answered by manshikumari10022006
0

Answer:

s.i = 10,000×12×3/100 = 3600.

A/q = Here interest is compounded half yearly .

A= p(1+r/200)²n = 10,000 (1+20/200)⁶

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