Question

Santosh of physical education teacher arrange three groups of 140, 91 and 63 students for the march past .if he arrange the same number of students in each row find the number of students arrange in each row.

Answer 1

Answer :

A physical education teacher arranged three groups 140 , 91 ,and 63 students for the march past.
And
He arranged the same number of students in each rows .

So, We find HCF of ( 140 , 91 and 63 ) 

140 = 2 × 2 × 5 × 7
And
91 = 7  × 13
And

63  = 3 × 3 × 7 

So,

HCF of ( 140 , 91 and 63 )   = 7 

Then we can say

The number of students he arranged in each row = 7( Ans )

Answer 2

Answer:

Step-by-step explanation: