Math, asked by kumarsukesh12194866, 8 months ago

Sanvi purchased some books for Rs. 120. If she purchased 3 more books
for the same amount each book would have cost her Rs. 2 less. Find the
number of books purchased by Sanvi and the price of each book.​

Answers

Answered by Anonymous
22

\blue{\bold{\underline{\underline{Answer:}}}}

 \:\:

 \green{\underline \bold{Given :}}

 \:\:

  • Sanvi purchased some books for Rs. 120

 \:\:

  • If she purchased 3 more books for the same amount each book would have cost her Rs. 2 less

 \:\:

 \red{\underline \bold{To \: Find:}}

 \:\:

  • Number of book sanvi purchased and the price of each book.

 \:\:

\large{\orange{\underline{\tt{Solution :-}}}}

 \:\:

Let Sanvi purchased 'x' numbers of books.

Let the price of 1 book be 'y'

 \:\:

 \underline{\bold{\texttt{We know that :}}}

 \:\:

 \red{\bold{Cost \: of \: 1 \: book \: = \: \dfrac {total \: cost } { total \: books \: purchased } }}

 \:\:

 \underline{\bold{\texttt{Cost of 1 book :}}}

 \:\:

 \bf \dashrightarrow y = \dfrac { 120 } { x } -----(1)

 \:\:

 \purple{\underline \bold{According \: to \: the \ question :}}

 \:\:

If she purchased 3 more books for the same amount each book would have cost her Rs. 2 less.

 \:\:

Hence,

 \:\:

 \sf \longmapsto \dfrac { 120 } { x + 3 } = y - 2

 \:\:

 \bf \dashrightarrow \dfrac { 120 } { x + 3 } + 2 = y ------(2)

 \:\:

 \underline{\bold{\texttt{We got that :}}}

 \:\:

 \purple{\bold{Equation \: (1) \: = \: Equation \: (2)}}

 \:\:

 \sf \longmapsto \dfrac { 120 } { x + 3 } + 2 = \dfrac { 120 } { x }

 \:\:

 \sf \longmapsto \dfrac { 120 + 2x + 6 } { x + 3 } = \dfrac { 120 } { x }

 \:\:

 \sf \longmapsto 120x + 2x^2 + 6x = 120x + 360

 \:\:

 \sf \longmapsto 2x^2 + 6x - 360 = 0

 \:\:

 \underline{\bold{\texttt{Dividing the above equation by 2}}}

 \:\:

 \sf \dashrightarrow x^2 + 3x - 180 = 0

 \:\:

 \underline{\bold{\texttt{Splitting middle term}}}

 \:\:

 \sf \longmapsto x^2 + 15x - 12x - 180 = 0

 \:\:

 \sf \longmapsto x(x + 15) -12(x + 15)

 \:\:

 \sf \longmapsto (x - 12)(x + 15)

 \:\:

  • x = 12

 \:\:

  • x = -15

 \:\:

As number of books can't be negative, Hence x = 12

 \:\:

 \underline{\bold{\texttt{Putting x = 12 in (1)}}}

 \:\:

 \sf \longmapsto y = \dfrac { 120 } { 12 }

 \:\:

 \bf \dashrightarrow y = 10

 \:\:

Hence she purchased 12 books and price of each book is 10 rupees

 \:\:

\rule{200}5

Similar questions