Sanvi purchased some books for rupees 120 if you purchased 3 more books for the same amount each book would have cost rupees 2 less .Find the number of books purchase by Saanvi and the price of each book.
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Step-by-step explanation:
c= cost per book
n= number of books
Given: Total cost of books=120 rupees
i.e. (c) x (n) = 120 ...(1)
also, if 3 books extra and cost per book is 2 rupees less, then
(c-3) x (n-2) = 120
or cn + 6 -3n -2c = 120
or 120 + 6 -3n -2c =120 [From (1), cn=120]
or 6 = 3n-2c
or 2c = 3n -6
or c=(3n-6)/2
Substituting in eq(1)
(n)(3n-6)/2 = 120
or 3(n-2)(n)/2=120 [Taking 3 common]
or (n-2)(n)= (120 x 2)/3
or n^2 - 2n = 80
or n^2 - 2n -80 =0
or (n-10)(n+8)=0
or n = 10 or (-8)
but n cant be negative
hence number of books purchased is n=10
and cost of each book is c=120/n=120/10=12
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