Question

Sanya has a piece of land which is in the shape of a rhombus.She wants her one daughter and one son to work and produce different crops to suffice the needs of their family .She divided the land into two equal parts.if the perimeter of the land is 400 m and one of diagonal is 160 m ,how much area each of them will get? What value is depicted by her by dividing the land equally for producing crops to suffice the needs of their family?

Answer 1

Answer:

$perimeter \: = 400m \\ each \: side \: = 400 \: \div \: 4 \: = \: 100m \\ bd \: = 160m \\ s = \frac{100 + 100 + 160}{2}m = 180m \\ \\ area \: of \: triangle =$

Answer 2

4800 m^2 is the area each will get.

The value of 'equality' is displayed by dividing the land equally for producing crops to suffice the needs of their family.

Step-by-step explanation:

Consider ABCD to be the rhombus-shaped field with

Perimeter = 400m

The measure of each side = Perimeter/4

= 400/4

= 100m

∵ AB = AD = 100m

Given that,

Considering BD to be the diagonal = 160 m

To find,

Semi-perimeter of the ΔABD i.e. s

= (100 + 100 + 160)/2

= 180m

Using heron's formula, we can find;

= $\sqrt{180(180 - 100) (180 - 100) (180 - 160)}$

= $\sqrt{180 * 80 * 80 * 20}$m^2

= 4800m^2

Thus, each daughter and son would get 4800m^2 land.

Learn more: area of the land

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