Math, asked by mythilimorampudi63, 10 hours ago

Sanya has a piece of land which is in the shape of a rhombus. She wants her daughter and son to work on the land and produce different crops to suffice the need of their family. She divided the land into equal parts. If the perimeter of the land is 400m and one of the diagonal is 160m, how much area will each of them get?

Answers

Answered by mokshitha380
2

Answer:

pls Mark as brainalist

Step-by-step explanation:

4800 m^2 is the area each will get.

The value of 'equality' is displayed by dividing the land equally for producing crops to suffice the needs of their family.

Step-by-step explanation:

Consider ABCD to be the rhombus-shaped field with

Perimeter = 400m

The measure of each side = Perimeter/4

= 400/4

= 100m

∵ AB = AD = 100m

Given that,

Considering BD to be the diagonal = 160 m

To find,

Semi-perimeter of the ΔABD i.e. s

= (100 + 100 + 160)/2

= 180m

Using heron's formula, we can find;

= \sqrt{180(180 - 100) (180 - 100) (180 - 160)}

180(180−100)(180−100)(180−160)

= \sqrt{180 * 80 * 80 * 20}

180∗80∗80∗20

m^2

= 4800m^2

Thus, each daughter and son would get 4800m^2 land.

Learn more: area of the land

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