Sanya purchased 2 bamboo tote bags and 3 show pieces for ₹ 5650 whereas Yamini purchased 3 bamboo tote bags and 2 show pieces for ₹7100. Find the cost of one tote bag and one show piece graphically.
Answers
Given :- Sanya purchased 2 bamboo tote bags and 3 show pieces for ₹ 5650 whereas Yamini purchased 3 bamboo tote bags and 2 show pieces for ₹7100.
To Find :- The cost of one tote bag and one show piece ?
Answer :-
Let us assume that, cost of one tote bag is Rs.x and cost of one show piece is y .
so,
→ 2x + 3y = 5650 ------- Eqn.(1)
→ 3x + 2y = 7100 ------- Eqn.(2)
multiply Eqn.(1) by 3 and Eqn.(2) by 2 and subtracting the result we get,
→ 3(2x + 3y) - 2(3x + 2y) = 3*5650 - 2*7100
→ 6x - 6x + 9y - 4y = 16950 - 14200
→ 5y = 2750
→ y = Rs.550
putting value of y in Eqn.(1)
→ 2x + 3*550 = 5650
→ 2x = 5650 - 1650
→ 2x = 4000
→ x = Rs.2000 .
therefore, The cost of one tote bag is Rs.2000 and one show piece is Rs.550 .
Learn more :-
JEE mains Question :-
https://brainly.in/question/22246812
. Find all the zeroes of the polynomial x4
– 5x3 + 2x2+10x-8, if two of its zeroes are 4 and 1.
https://brainly.in/question/39026698