Question

Sanya visits her friends with a basket of chocolates.She gives 1/3 of the chocolates to the first friend.She gives 4/5 of the remaining chocolates to the second friend.3/4 of the remaining chocolates was divided into two halves and given to the remaining two friends.What fraction of the chocolates was she left with?

Answer 1

Answer:

Hey , suppose she have ' x ' chocolates.

She gave x / 3 chocolates to her friend, so now she haves 2x / 3 chocolates.

Hence ,

Chocolates Given = x / 3

Chocolates Remaining = 2x / 3

Now , she gave 4 / 5 of remaining chocolates.

So ,

Chocolates Given =( 4 / 5 ) × ( 2x / 3 ) = 8x / 15.

Chocolates Remaining =( 2x / 3 ) - ( 8x / 15 ) = 2x / 15

Now , she gave 3 / 4 of remaining to other two friends ,

So ,

Chocolates Given = ( 3 / 4 ) × ( 2x / 15 ) = x / 10

Chocolates Remaining = ( 2x / 15 ) - ( x / 10 )

= x / 30.

Hence , if numbe of chocolates in basket was ' x ' then , the fraction she is having after distribution is x / 30.

Hence , she was lefted with 1 / 30 (th) part of total chocolates.