Question

Sapphire and Abe are shelving books at a public library. Sapphire shelves 5 books at a time, whereas

Abe shelves 6 at a time. If they end up shelving the same number of books, what is the smallest

number of books each could have shelved​

Answer 1

Answer:

30

To find it,find the LCM of 5 and 6.

That is 5×6=30

Answer 2

$Number \: of \: books \: Sapphire \: shelves \\at\:a \: time = 5$

$Number \: of \: books \: Abe \: shelves \\at\:a \: time = 6$

/* According to the problem given , we have to find LCM of 5 and 6*/

$LCM \:of \:5 \:and \: 6 = 30$

Therefore.,

$\red{ The \: smallest \:number \:of \:books }\\\red{ each \: could \:have \: shelved } \green {=30}$

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