Physics, asked by kuldeeptripathi1070, 1 year ago

Sara has a fire in the fireplace to warm her 20°C apartment. She realizes that she has left the iron poker in the fire. How hot is the fire if the 0.60 m poker lengthens 0.30 cm? (αiron = 12 x 10-6°C-1)

Answers

Answered by shreshth1241
1

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Answered by topanswers
2

Answer:

Fire is at temperature of 437°C

Explanation:

Due to heat, the iron rod expands. This phenomenon is called as Linear Thermal Expansion, which is given by the equation:

Δ L / L = α  Δ T

Where ,

Δ L is the change in length of the iron poker = 0.3 cm = 0.003 m

L is the Original length of the iron poker = 0.6 m

α   is the linear expansion coefficient of iron =  12 x 10^-6 °C^-1

Δ T is the change in temperature.

Δ T = T2- T1

T1 is the initial temperature = 20°C

T2 is the temperature of fire.

So,

T2 - T1 = Δ L / L * α

T2 - 20 = 0.003 / (0.6 * 12 x 10^-6 )

T2 =  417 + 20

T2 = 437 °C

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