Question

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Q1.A father is 3 times as old as his son. In 10 years’ time, his age will be double his son’s age. Find their present ages.​

Answer 1

Explanation:

let the present age of son be x years

then his father age= 3x

After 10 years

Son's age = (x+10) years

father's age=(3x+10)years

According to question

3x+10=2(x+10)

3x+10=2x+20

x= 10

Present age of son = 10years

His father's age= 30years

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Answer 2

Answer:

son age is 10 year old.

Father age is 30 years old.

Explanation:

Let say:

F= Father’s age

S = Son's age

For (Eq1) Father is three times as old as his son:

F = 3S

For (Eq2) In 10 year time the Father age will be twice as old as his son:

F + 10 = 2(S + 10)

F=2S+20–10

F=2S+10 (Eq2)

Then, lets us substitute the (Eq1) into the (Eq2)

3S=2S+10

3S-2S=10

S=10

Then son is 10 years old.

and Father

F=3S so 3 x 10

Father age is 30 years old.

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