Sara’s age is 23 years more than half of shama’s age. Five years ago the sum of their ages was
55 years. Find their present ages.
Solution: let sara’s age be x years and shama’s age be y years.
According to the first condition
x =
y/2+23
– y = 46 …..(I)
Five years ago sara’s age = x – 5
And shama’s age was = ______
Sum of their ages = 55
According to the second condition
(x– 5) + (y – 5) = 55
x + y = ………(II)
Adding equation (I) and (II)
2x – y = 46
x + y = 65
____ = 111
x = 37
Substituting x = 37 in equation (I)
x +y = 65
y = ____
∴ The present age of sara is 37 years and shama’s presnt age is _____years.
Answers
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let sara’s age be x years and shama’s age be y years.
According to the first condition
x = 32
y/2+23
– y = 46-23 (I)
Five years ago sara’s age = x – 5
And shama’s age was = 23
Sum of their ages = 55
According to the second condition
(x– 5) + (y – 5) = 55
x + y = 65 (II)
Adding equation (I) and (II)
2x – y = 46
x + y = 65
46+ 65 = 111
x = 37
Substituting x = 37 in equation (I)
x +y = 65
y = 28
∴ The present age of sara is 37 years and shama’s present age is 28 years.
Explanation:
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