Question

सर्वसमिका का प्रयोग करके मान ज्ञात कीजिए-
$1.(z ^{2} + 2)(z ^{2} - 3) \: \\ 2.(y + 6)(y - 4) \\ 3.(x + 7)(x + 9)$
please with full solution
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Answer 1

Step-by-step explanation:

$(z ^{2} + 2)( {z}^{2} - 3) \\ = {z }^{2} \times {z}^{2} + 2 {z}^{2} - 3 {z}^{2} - 6 \\ = {z}^{4} + 2 {z}^{2} - 3 {z}^{2} - 6 \\ = {z}^{4} - {z}^{2} - 6 \\ 2.(y + 6)(y - 4) \\ = {y}^{2} + 6y - 4y - 24 \\ {y}^{2} + 2y - 24 \\ 3.(x + 7)(x + 9) \\ = {x}^{2} + 7x + 9x + 63 \\ {x}^{2} + 16x + 63$

I hope this help you

Answer 2

Answer:

Your answer is here

1. Y^2+2y-24

2. X^2+16x+63

3. Z^4-z^2-6

Hope it will help you

Plz marks as brainlist answers

Thank u