Question

sarah is five years older than saniya. if four more than four times saniya's age is three less than three times sarah's age, what are their ages? ​

Answer 1

The ages of sarah and saniya are 13 and 8 years old

Solution:

Sarah is Five years old than Saniya

So let's the age of Saniya = x  

So the age of Sarah = x +5

According to question

four more than four times saniya's age = three less than three times sarah's age

4 + 4x = 3(x+5) - 3

4 + 4x = 3x + 15 -3

4 + 4x = 3x + 12

x = 12 - 4 = 8

So Saniya's age = 8  

And Sarah's age = 8 + 5 = 13

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Answer 2

Answer:

Saniya's age = 8 years,

And, Sarah's age = 13 years.

Step-by-step explanation:

Let the age of Saniya = x years,

∵ Sarah is five years older than Saniya.

Age of Sarah = (x + 5) years,

According to the question,

$4(x) + 4 = 3(x+5) - 3$

$4x+4=3x+15-3$

$4x+4=3x+12$

$4x-3x = 12-4$

$x=8$

Hence, Saniya's age = 8 years,

And, Sarah's age = 13 years.