Question

सरकरूप दया: (4x²+ 7x -1)-(x²+Bx-7) +(x²+10)​

Answer 1

Answer:

(4x²+ 7x-1) -x²-bx +7+(x²+10)

= 4x²+ 7x-1 -x²-bx +7+ x²+10

=4x²+x²-x²+ 7x-bx+17-1

=4x²+x²-x²+ 7x-bx+16

= 4x²+7x-bx+16

= 4x²+7-b+16

=4x²+23-b