Question

सरल कीजिए: (i) $2^{2/3} \cdot 2^{1/5}$
(ii) ${(\frac{1}{{3}^3})}^7$
(iii)$\frac{11^{1/2}}{11^{1/4}}$
(iv) $7^{1/2} \cdot 8^{1/2}$

Answer 1

Answer:

Answer is in the pic. ↑↑

Step-by-step explanation:

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Answer 2

Answer:

Step-by-step explanation:

हल :  

(i) दिया है : 2^⅔  . 2^⅕

2^⅔  . 2^⅕ = (2)^(⅔+¹/5)

= 2^(10+3)/5

[xᵃ . xᵇ = xᵃ⁺ᵇ]

= 2^13/5

अतः, 2^⅔  . 2^⅕ = 2^13/5

(ii) दिया है : (⅓³)⁷

(⅓³)⁷ = ⅓²¹

[(xᵃ)ᵇ = xᵃᵇ]

= 3^-21

अतः,  (⅓³)^7 = 3^-21

(iii) दिया है : 11^½/11^¼

11^½/11^¼ = 11^½ - ¼

[xᵃ / xᵇ = xᵃ⁻ᵇ]

= 11^(2 -1)/4

= 11^¼

अतः, 11^½/11^¼ = 11^¼

(iv) दिया है : 7^½ . 8^½

7^½ . 8^½ = (7.8)^½

[xᵃ .yᵇ = (xy)ᵃᵇ]  

= 56^½

अतः, 7^½ . 8^½ = 56^½

आशा है कि यह उत्तर आपकी मदद करेगा।।।

56¹

इस पाठ से संबंधित कुछ और प्रश्न  :

ज्ञात कीजिए: (i)  64^\frac{1}{2} (ii) 32^\frac{1}{5}  (iii) 125^\frac{1}{3}

https://brainly.in/question/10164936

ज्ञात कीजिए: (i) $9^{3/2}$ (ii) $32^\frac{2}{5}$ (iii)$16^\frac{3}{4}$ (iv) $125^\frac{-1}{3}$

https://brainly.in/question/10164937