सरल कीजिए और उत्तर को धनात्मक घातांक के रूप में व्यक्त कीजिए। (i) (ii) (iii) (iv) (v) [tex] 2^{- 3} \times (-7)^{- 3} [/tex
Answers
Answer Explanation:
i) (- 4)⁵÷ (-4)⁸ = (- 4)⁵ ⁻ ⁸
[a^m ÷ a^n = a^m-n]
= (- 4)-³
= 1/(- 4)³
[a^-m = 1/ am]
= -1/64
(ii) (1/2³)² = 1²/(2³)²
[(a/b)m = am/bm]
= 1/ 2³×²
[(a^m)^n = a^mn]
= ½⁶
= 1/64
(iii) (-3)⁴ × (5/3)⁴ = (- 3)⁴ × (5⁴/3⁴ )
[(a/b)m = am/bm]
= (3)⁴ × (5⁴/3⁴)
= (3)⁴ ⁻ ⁴ × 5⁴
= 3⁰ × 5⁴
= 1 × 5⁴
[a⁰ = 1]
= 5⁴
(iv) (3⁻⁷ ÷ 3⁻¹⁰) × 3⁻⁵
= 3 ⁻⁷ ⁺ ¹⁰ ⁻⁵
[a^m ÷ a^n = a^m- n]
= 3³ ⁻ ⁵
= 3 ⁻²
= ⅓²
[a^⁻ m = 1/ a^m]
(v) 2 ⁻³ × (-7)⁻³
= [2 × -7]⁻³
[a^m × b^m = (ab)^m]
= [ -14]⁻³
= - 1/14³
[a^⁻m = 1/ am]
आशा है कि यह उत्तर आपकी अवश्य मदद करेगा।।।।
इस पाठ से संबंधित कुछ और प्रश्न :
मान ज्ञात कीजिए : (i) (ii) (iii)
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मान ज्ञात कीजिए : (i) (ii) (iii) (iv) (v)
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