Question

सरळरूप द्या : ( 4x 2 + 7x − 1) − ( x2 + 8x − 7) + ( x2 + 10)
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Answer 1

Answer:

4x²-x+16

Step-by-step explanation:

=4x²+7x-1-x²-8x+7+x²+10

=4x²+7x-8x-1+7+10

=4x²-x+16

Answer 2

Given:

An equation $(4x^2+7x-1)-(x^2+8x-7)+(x^2+10)$.

To Find:

The resultant of the given equation.

Solution:

The BODMAS rule, where firstly brackets are removed followed by Order, Division, Multiplication, Addition, and Subtraction will be used here to perform the indicated operations in the given equation.

Remove all the brackets from the equation.

$4x^2+7x-1-x^2-8x+7+x^2+10$

Now, group the like terms.

$4x^2-x^2+x^2+7x-8x+7+10-1$

Combine the grouped terms.

$4x^2-x+16$

Thus, $4x^2-x+16$ is the result obtained after simplifying the given equation.