Question

Sardis was drawing a triangle. The first segment he drew was 10 centimeters. The 2nd side he drew was 12 centimeters. How long would the 3rd side have to be to create a triangle? Watch the video for support.

Answer 1

$\mathrm{Question}$

Sardis was drawing a triangle. The first side he drew was 10 centimeters. The 2nd side he drew was 12 centimeters. How long would the 3rd side have to be to create a triangle?

$\mathrm{Solution}$

Let the third side be x

Given two sides are 10, 12 cm respectively.

According to Laws of Triangle

The sum of two sides should be greater than the third side.

⇒ 10 + 12 > x

⇒ 22 > x

The sum of two sides should be greater than the third side.

⇒ 10 + x > 12

⇒ x > 12 - 10

⇒ x > 2

(or)

The difference of two sides should be less than the third side.

⇒ 12 - 10 < x

⇒ 2 < x

The difference of two sides should be less than the third side.

⇒ x - 10 < 12

⇒ x < 12 + 10

⇒ x < 22

Therefore, The third side can be of length 2 < x < 22

Answer 2

Answer:

Question

Sardis was drawing a triangle. The first side he drew was 10 centimeters. The 2nd side he drew was 12 centimeters. How long would the 3rd side have to be to create a triangle?

\mathrm{Solution}Solution

Let the third side be x

Given two sides are 10, 12 cm respectively.

According to Laws of Triangle

The sum of two sides should be greater than the third side.

⇒ 10 + 12 > x

⇒ 22 > x

The sum of two sides should be greater than the third side.

⇒ 10 + x > 12

⇒ x > 12 - 10

⇒ x > 2

(or)

The difference of two sides should be less than the third side.

⇒ 12 - 10 < x

⇒ 2 < x

The difference of two sides should be less than the third side.

⇒ x - 10 < 12

⇒ x < 12 + 10

⇒ x < 22

Therefore, The third side can be of length 2 < x < 22

$<marquee> hi$