Math, asked by neeta69, 1 year ago

Sarita is 14 years younger than her cousin after 5 years their ages will be in the ratio 2 : 3 find their present ages

Answers

Answered by adee1729
94
let cousin's age=a,

Sarita's age=(a-14),

(a-14+5)/(a+5) =2/3,

(a-9)/(a+5) =2/3,

3a-27=2a+10,

3a-2a=10+27,

a=37 yrs,

cousin's age=37 yrs,

Sarita's age=(37-14)=23yrs
Answered by poonamkumargupta4420
14

The present age of a cousin is 'x'

then the present age of Sarita is x +14

After 5 years

The age of her cousin will be (x+5)

Age of Sarita will be (x+14 +5) = solve it (x+19)

A.T.Q

X+5. 2

-----. = ----

x+19. 3

3 x +15 = 2x+38

3x - 2x= 38-15

x=23

Present age of her cousin is 23

then age of Sarita is = 23+14

=37

hope it helps

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