Question

Sarita's mother's age is 4 times as old as her,twenty years later she will be just twice as old as Sarita find the present age of Sarita. guys answer fast please​

Answer 1

Answer:

X=10

Step-by-step explanation:

Let sarita's age be x, then her mother's age= 4x

agter 20 years their age will be:sarita's=x+20, mother's= 4x+20

after 20 years she will be twice sarita's age. so:

4x+20=2(x+20)

=4x+20= 2x+40

=4x-2x=40-20

=2x=20

=x=10

therefore sarita is 10 years old

Answer 2

Answer:

Let Sarita's age be x years .

Then Mother's age = 4x .

After 20 years , Sarita's age = x+20

Mother's age = 4x+20

But According to question ,

After 20 years , Mother's age = 2 (as old as Sarita)

4x+20 = 2(x+20)

4x+20 = 2x +40

4x-2x =40-20

2x = 20

x=10

So , present age of Sarita = 10 years

So , present age of Sarita = 10 years Mother's present age = 4×10 = 40 years