Question

Sarita starts at 8:00AM by bicycle to reach school. She cycles at the speed of 18km/hours and reaches the school at 8:22 AM. By how much should she increase the spped so that she can reach the school at 8:12 AM? ​

Answer 1

Answer:

Answer is 33 km/hours

Step-by-step explanation:

for 18 km she take 22 minutes to reach the school if for the same distance to cover in 12 minutes .

=( 18 x 22)/12= 33

Hence she has to increase speed to 33 km/ hours.

Answer 2

The speed required is 9.82 km/hours.

Step-by-step explanation:

According to the given information, Sarita starts at 8:00AM by bicycle to reach school and she cycles at the speed of 18km/hours and reaches the school at 8:22 AM. This means, it takes Sarita twenty two minutes to reach school by bicycle.

Now, first we need to convert 22 minutes into equivalent hours with the help of unitary method.

Now, 60 minutes are there in an hour.

This means, 1 minute is there in $\frac{1}{60}$ hours.

This means, 22 minutes are there in $\frac{22}{60}$ hours.

Now, according to the given information, we need to find how much she should increase the speed so that she can reach the school at 8:12 AM, which means if she starts at 8:00 AM, she should be reaching school in 12 minutes.

Now,

60 minutes are there in an hour.

This means, 1 minute is there in $\frac{1}{60}$ hours.

This means, 12 minutes are there in $\frac{12}{60}$ hours.

Then, we get by unitary method,

22 minutes are required by Sarita for reaching school at a speed of 18 km/hours.

Then, 1 minute is required by Sarita for reaching school at a speed of $\frac{18}{22}$ km/hours.

Then, 12 minutes are required by Sarita for reaching school at a speed of

$\frac{18 *12}{22} \\=\frac{9 *12}{11} \\\\=9.82 km/hours$

Thus, the speed required is 9.82 km/hours.

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