Question

Saritha and kavitha are separated by a certain distance of 100m and saritha started from her house and walked for 30m east and turned right and walked up to 10m and then turned left and walked up to 20m and again turned left and walked to the road. What is the distance between the two girls now?

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

The distance between kavitha and saritha is 150m

Step-by-step explanation:

Given that,Saritha and kavitha are seperated by a distance of 100m.We will solve this problem using co-ordinate geometry.

Assume that Kavitha is at point (0,0) and saritha is at (100,0).

Saritha walks 30m east hence her position becomes (100+30,0)=(130,0).

She turns 10m right hence her position is (130,-10)

She turns left 20m hence new position is (150,-10)

She again turns back and returns to road hence her position becomes (150,0)

Now the distance between kavitha and saritha is as follows

$d = \sqrt{(150 - 0) {}^{2} + (0 - 0) {}^{2} } \\ = 150m$

Hence,the distance between kavitha and saritha is 150m

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