Math, asked by Dnd1, 11 months ago

Saroj and kavita like to keep themselves physically fit. They jog daily in the morning saroj jogs around a rectangular park of
dimensions Cxy +yz)m and (xy-yz)m, Kavita jogs around a square park of side (2x+3y)m.
a) How much distance does Saroj cover in 5
rounds?
b) How much distance does Kavita coverin!
I round?
c) Find the area of each park.
d) Here which quality do Saroj and Kavita posses
solve step by step​

Answers

Answered by dasarivara58
3

Answer:

a) 20xy m

b)8x+12y m

C) area of rectangular park =(xy) ^2-(yz)^2

area of square park =4x+9y+24xy

d)

Step-by-step explanation:

a) saroj covers a distance of 4xy m in one round

Therefore perimeter of a rectangle = 2(a+b)

=2(xy+yz+xy-yz)

=2(2xy)=4xy

The distance covered by saroj in five rounds = 5(4xy)=20xy

b) kavitha covers a distance of 8x+12y in one round

Therefore perimeter of a square =4(side)

=4(2x+3y)

=8x +12y

c)area of rectangular park =(xy+yz) (xy-yz)

=(xy) ^2-(yz)^2

Area of square park = (2x+3y)^2

=(2x) ^2 +(3y)^2 + 2(2x)(3y)

=4x+9y+24xy

d) i didn't understand the question

I think L did it correct

Answered by Anonymous
1

Answer:

P t a

nhi................

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