Math, asked by shantichoudhary3680, 8 months ago


Sarthak invested certain amount
of money
in two schemes A & B.
which offer interest at the rate of
8% per annum and 9% per annum
respectively. He received rs.1860 annual
interest. However, had he interchange
the amount of investment in two
schemes, he would have received rs.20
as more as annual interest How
did he invest in each
school?
much money​

Answers

Answered by pinky78998
0

Answer:

Let amount invested in A be Rs. x and in B be Rs. y.

As per the given statements,

0.08x+0.09y=1860.....(1)

And, 0.09x+0.08y=1880.....(2)

Multiplying equation (1) with 8 we get, 0.64x+0.72y=14880.....(3)

Multiplying equation (2) with 9 we get, 0.81x+0.72y=16920.....(4)

Subtracting equation (3) from (4), we get 0.17x=2040=>x=12000

Substituting x=12000 in the equation (1), we get 0.08(12000)+0.09y=1860⇒y=10000

Hence, amount invested A is Rs. 12000 and in B is Rs. 10000

Step-by-step explanation:

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Answered by ItzAaryan
0

ur answer is 10000 RS....

hope it helps you...

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