satellite of mass m is revolving round the earth at a height R above the surface of earth. If g is gravitational acceleration at surface of earth and R is radius of earth then magnitude of momentum of satellite is k
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Answer:
At a height h, acceleration due to gravity be g
′
As, g
′
=g(1+
R
h
)
−2
Now, for h=R,⟹g
′
=
4
g
potential energy, P.E=−
(R+h)
GMm
, and g
′
=
(R+h)
2
GM
⟹P.E=−mg
′
(R+h)
For h=R,P.E=−m×
4
g
×2R
Thus, P.E=−
2
mgR
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