Satellite revolving around the earth at the height of 400 km above the earth's surface has a time period of about
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The time period of the given satellite around the earth will be 92.61 minutes.
- Radius of earth, R = 6400 km = 6400 × 10³ m
Height of satellite, H = 400 km = 400 × 10³m
- Formula for time period of the satellite is
T = 2π/R √[(R+H)³/g]
= 2 × 3.14/(6400 × 10³) × √[(6400 × 10³ + 400 × 10³)³/9.8]
= 9.81 × 10⁻⁷ × √[3.144 × 10²⁰ /9.8]
= 9.81 × 10⁻⁷ × 1.773 × 10¹⁰/3.13
= 3.134 × 1773 =5556.58 sec = 92.61 minutes
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Satellite revolving around the earth at the height of 400 km above the earth's surface has a time period of about
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