Question

- Sathi has drawn a right-angled triangle whose length of the hypotenuse
the twice of the shortest side. If the length of the third side is 2 cm. less than the length of the
hypotenuse, then by calculating, let us write the lengths of three sides of the right-angled
triangle drawn by Sathi.
jega
nit digit then the product is 189 and if the by applying sridhara Acharya's formula​

Answer 1

Answer:

Step-by-step explanation:

AB  

2

+AC  

2

=BC  

2

 

⇒x  

2

+(4+2x)  

2

=(6+2x)  

2

 

⇒x  

2

+16+4x  

2

+16x=36+4x  

2

+24x

⇒x  

2

+16−36+16x−24x=0

⇒x  

2

−8x−20=0

⇒x  

2

−10x+2x−20=0

⇒x(x−10)+2(x−10)=0

⇒(x+2)(x−10)=0

∴x



=−2, x=10

[side cannot be negative]

Therefore, sides are Hypotenuse=6+2(10)=26

Base=10

Perpendicular=4+2(10)=24.

Answer 2

I solve it and also explain it very well

if ans is best then mark me in the brainlist