Math, asked by Keerthan2396, 1 year ago

Sathis is two years older than mahesh...abhay is as twice as mahesh.ryan is as twice as abhay.the sum of their age is 42 years..how old is sathish

Answers

Answered by Anonymous
103

Solution :-

Let the present age of Sathis be x years.

Mahesh's age = (x - 2) years

Abhay's age = 2(x - 2) years

Aryan's age = 4(x - 2) years

According to the question,

=> x + x - 2 + 2(x - 2) + 4(x - 2) = 42

=> x + x - 2 + 2x - 4 + 4x - 8 = 42

=> 8x = 42 + 14

=> x = 56/8 = 7

Hence,

Sathis's age = x = 7 years

Answered by Anonymous
18

SOLUTION

Let the Satish's age be x.

Mahesh's age= (x-2)

Abhay's age = 2(x-2)

Ryan's age = 4(x-2)

Sum of their ages = 42

Therefore,

=)x+ x-2+2(x-2)+4(x-2)= 42

=)x+x-2+2x-4+4x-8= 42

=) 8x- 14= 42

=) 8x= 42+14

=) 8x= 56

=) x= 56/8

=) x= 7

Satish is 7 years old

hope it helps ☺️

Similar questions