Sathish is going on 2100 road trip with 2 friends whom he will pick up 150 kilometers after he begins the trip and drop off when there are 150 kilometer remaining the car consumes 6 liters of gas for every 100 kilometers and gas cost 1.20 per liter how much will Sathish pay for gas
Answers
Answer:
151.2
Step-by-step explanation:
2100 km/ 100 km=21
21 *6 liters=126 liters
126 liters *1.2= 151.2
Answer: Sathish will pay a total of \$64.80$64.80dollar sign, 64, point, 80 for gas.
Step-by-step explanation:Sathish pays for all of the gas when he is alone in the car, and he pays for \dfrac{1}{3}
3
1
start fraction, 1, divided by, 3, end fraction of the gas when his friends are with him.
Hint #22 / 5
Sathish travels 300\,\text{km}300km300, start text, k, m, end text alone. The car consumes 666 liters of gas for every 100100100 kilometers.
300\,\cancel{\text{km}}\times \dfrac{6\,\text{L}}{100\,\cancel{\text{km}}}=18\,\text{L}300
km
×
100
km
6L
=18L300, start cancel, start text, k, m, end text, end cancel, times, start fraction, 6, start text, L, end text, divided by, 100, start cancel, start text, k, m, end text, end cancel, end fraction, equals, 18, start text, L, end text
Sathish uses 18\,\text{L}18L18, start text, L, end text of gas when he is alone.
Gas costs \$1.20$1.20dollar sign, 1, point, 20 per liter.
18\,\cancel{\text{L}} \times 1.20\dfrac{\$}{\cancel{\text{L}}}=\$21.6018
L
×1.20
L
$
=$21.6018, start cancel, start text, L, end text, end cancel, times, 1, point, 20, start fraction, dollar sign, divided by, start cancel, start text, L, end text, end cancel, end fraction, equals, dollar sign, 21, point, 60
Sathish pays \$21.60$21.60dollar sign, 21, point, 60 for gas when he is alone in the car.
Hint #33 / 5
There are 333 people in the car for 1800\,\text{km}1800km1800, start text, k, m, end text because 2100-2\times 150=18002100−2×150=18002100, minus, 2, times, 150, equals, 1800.
1800\,\cancel{\text{km}}\times \dfrac{6\,\text{L}}{100\,\cancel{\text{km}}}=108\,\text{L}1800
km
×
100
km
6L
=108L1800, start cancel, start text, k, m, end text, end cancel, times, start fraction, 6, start text, L, end text, divided by, 100, start cancel, start text, k, m, end text, end cancel, end fraction, equals, 108, start text, L, end text
Sathish uses 108\,\text{L}108L108, start text, L, end text of gas when his friends are in the car.
108\,\cancel{\text{L}} \times 1.20\dfrac{\$}{\cancel{\text{L}}}=\$129.60108
L
×1.20
L
$
=$129.60108, start cancel, start text, L, end text, end cancel, times, 1, point, 20, start fraction, dollar sign, divided by, start cancel, start text, L, end text, end cancel, end fraction, equals, dollar sign, 129, point, 60
Sathish and his 222 friends split the cost of the \$129.60$129.60dollar sign, 129, point, 60 worth of gas equally.
129.60\times \dfrac{1}{3}=43.20129.60×
3
1
=43.20129, point, 60, times, start fraction, 1, divided by, 3, end fraction, equals, 43, point, 20
Sathish pays \$43.20$43.20dollar sign, 43, point, 20 for gas when his friends are in the car.
Hint #44 / 5
21.60+43.20=64.8021.60+43.20=64.80