Question

Sati and Savitri visited three temples to offer flowers At the first temple, Sati offered two-third of her flowers, plus one extra flower. At the second temple also she offered two-third of her flowers, and an extra flower. After repeating the process at the third temple, she was left with one flower. Savitri started with the same number of flowers as Sati. but offered 20 flowers at each temple How many flowers did Savitri have left after visiting the third temple?

Answer 1

To calculate flowers

Given:

• Sati offered two-third of flowers, plus one extra flower. After the offering at the third temple, she was left with one flower.
• Savitri offered 20 flowers at each temple.

To find: How many flowers did Savitri have left after visiting the third temple?

Solution: Let total number of flowers be x.

At the first temple:

• Total flowers = x
• Flowers offered = $\frac{2}{3}x+1$
• Flowers left = $x -(\frac{2}{3}x + 1)$
• = $\frac{1}{3}x - 1$

At the second temple:

• Total flowers = $\frac{1}{3}x - 1$
• Flowers offered = $\frac{2}{3}(\frac{1}{3}x-1)+1$
• = $\frac{2}{9}x+\frac{1}{3}$
• Flowers left = $\frac{1}{3}x-1-(\frac{2}{9}x+\frac{1}{3})$
• = $\frac{1}{9}x-\frac{4}{3}$

At the third temple:

• Total flowers = $\frac{2}{3}(\frac{1}{9}x-\frac{4}{3})+1$
• = $\frac{2}{27}x+\frac{1}{9}$
• Flowers left = $\frac{2}{27}x+\frac{1}{9}-(\frac{2}{27}x+\frac{1}{9})$
• = $\frac{1}{27}x-\frac{11}{9}$

By the given condition,

$\quad \frac{1}{27}x-\frac{11}{9}=1$

$\Rightarrow \frac{1}{27}x=1+\frac{11}{9}$

$\Rightarrow \frac{1}{27}x=\frac{20}{9}$

$\Rightarrow x=\frac{20\times 27}{9}$

$\Rightarrow x=60$

So total number of flowers is 60.

• Savitri also had 60 flowers in total.
• In each temple, she offered 20 flowers.
• In three temples, she offered (20 × 3) = 60 flowers.
• Flowers left = 60 - 60 = 0

Answer: Savitri was left with no flowers.

Answer 2

Answer: Savitri is left with 6 flowers