Question

satisfies all the conditions of Rolle's
x² – 3x
For which interval, the function
x-1
theorem
>
[0.3]
[-3.0]
[1.5.3)
> For no interval​

Answer 1

• Here, f(x) = (x2 - 3x)/(x - 1) ⇒ - sinc = - 2/π ⇒ c = sin-1(2/π) Obviously, it is not derivable at x = 1, that is, in (0, 3). Also, f(a) = f(b) does not hold for [ 3, 0] − and [1. 5, 3}