Satisfies the conditions of the problem.
EXERCISE 3.6
1. Solve the following pairs of equations by reducing them to a pair of linear equations:
1
1
3 y
= 2
2x
Nl who
ve
2 3
+
X
y
I
1
1
13.
+
4
9
3x
2 y
6
1/
-1
Sx
x 5
5
4
-- + 3y = 14
X
1
(iv)
+
*
= 2
x - 1
y – 2
6
3
3
– =
4y = 23
= 1
X - 1
y - 2
7x27 -5
(v)
(vi) 6x + 3y=6xy
8x + 7y - 15
2x+4y=5xy
10
2
(viii)
=4
1
+
3x + y
1 _3
3х – у
4
(vii)
x+y
1
1
--1
15
5
8
2(3x + y) 2(3x - y)
X-
solutions:
Answers
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Answer:
1
1
3 y
= 2
2x
Nl who
ve
2 3
+
X
y
I
1
1
13.
+
4
9
3x
2 y
6
1/
-1
Sx
x 5
5
4
-- + 3y = 14
X
1
(iv)
+
*
= 2
x - 1
y – 2
6
3
3
– =
4y = 23
= 1
X - 1
y - 2
7x27 -5
(v)
(vi) 6x + 3y=6xy
8x + 7y - 15
2x+4y=5xy
10
2
(viii)
=4
1
+
3x + y
1 _3
3х – у
4
(vii)
x+y
1
1
--1
15
5
8
2(3x + y) 2(3x - y)
X-
solutions:
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