Question

Satish invested Rs.10000 at 10% p.a. compound interest compounded annually. After how

many years will he receive an amount of Rs.13310?​

Answer 1

Easy

Solution

Given:-

Correct option is A)

Correct option is A)Principal, P=Rs.10,000

Correct option is A)Principal, P=Rs.10,000Rate of interest =10%

Correct option is A)Principal, P=Rs.10,000Rate of interest =10%Time =3 years

Correct option is A)Principal, P=Rs.10,000Rate of interest =10%Time =3 yearsSo, n=3

Correct option is A)Principal, P=Rs.10,000Rate of interest =10%Time =3 yearsSo, n=3A=P(1+

Correct option is A)Principal, P=Rs.10,000Rate of interest =10%Time =3 yearsSo, n=3A=P(1+ 100

Correct option is A)Principal, P=Rs.10,000Rate of interest =10%Time =3 yearsSo, n=3A=P(1+ 100r

Correct option is A)Principal, P=Rs.10,000Rate of interest =10%Time =3 yearsSo, n=3A=P(1+ 100r

Correct option is A)Principal, P=Rs.10,000Rate of interest =10%Time =3 yearsSo, n=3A=P(1+ 100r )

Correct option is A)Principal, P=Rs.10,000Rate of interest =10%Time =3 yearsSo, n=3A=P(1+ 100r ) n

Correct option is A)Principal, P=Rs.10,000Rate of interest =10%Time =3 yearsSo, n=3A=P(1+ 100r ) n

Correct option is A)Principal, P=Rs.10,000Rate of interest =10%Time =3 yearsSo, n=3A=P(1+ 100r ) n A=Rs. 10,000(1+

Correct option is A)Principal, P=Rs.10,000Rate of interest =10%Time =3 yearsSo, n=3A=P(1+ 100r ) n A=Rs. 10,000(1+ 100

Correct option is A)Principal, P=Rs.10,000Rate of interest =10%Time =3 yearsSo, n=3A=P(1+ 100r ) n A=Rs. 10,000(1+ 10010

Correct option is A)Principal, P=Rs.10,000Rate of interest =10%Time =3 yearsSo, n=3A=P(1+ 100r ) n A=Rs. 10,000(1+ 10010

Correct option is A)Principal, P=Rs.10,000Rate of interest =10%Time =3 yearsSo, n=3A=P(1+ 100r ) n A=Rs. 10,000(1+ 10010 )

Correct option is A)Principal, P=Rs.10,000Rate of interest =10%Time =3 yearsSo, n=3A=P(1+ 100r ) n A=Rs. 10,000(1+ 10010 ) 3

Correct option is A)Principal, P=Rs.10,000Rate of interest =10%Time =3 yearsSo, n=3A=P(1+ 100r ) n A=Rs. 10,000(1+ 10010 ) 3 =Rs.13310

Correct option is A)Principal, P=Rs.10,000Rate of interest =10%Time =3 yearsSo, n=3A=P(1+ 100r ) n A=Rs. 10,000(1+ 10010 ) 3 =Rs.13310Amount=Rs.13,310

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