Question

Satish invested rs. 14,000 partially in scheme A which offer 20%p.a.at C.I.and remaining in scheme B which offer 25%at S.I .find the amount invested in scheme B if total interest earns after 2 years is rs.6640.?

Answer 1

Amount invested in Scheme B = 8000

Step-by-step explanation:

Let say Invested in CI at 20% = X

then Interest earned in 2 years = X(1 + 20/100)² - X

= 0.44X

Amount deposited in SI at 25% = 14000 - X

Interest Earned = (14000 - X) * 25 * 2 /100

= 7000 - 0.5X

Total interest = 0.44X + 7000 - 0.5X  = 6640

=> 0.06X = 360

=> X = 6000

Amount invested in Scheme B = 14000 - X = 14000 - 6000

= 8000

Learn more

If the difference between the ci and si

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Answer 2

The amount invested in Scheme B is Rs.8000

Step-by-step explanation:

Let the amount invested in Scheme A be x

Total amount = 14000  

Remaining amount invested in Scheme B = 14000-x

Scheme A

Principal = x

Rate of interest = 20% =0.20

Time = 2 years  

Using compound interest formula,

$A=P(1+r)^t$

$A=x(1+0.20)^2$

Amount = 1.44x

Compound interest = Amount - Principal = 1.44x -x = 0.44x

Scheme B

Principal = 14000-x

Rate of interest = 25%  

Time = 2 years  

$Si = \frac{P \times T \times R}{100}$

$Si = \frac{(14000-x) \times 2 \times 25}{100}$

Now we are given that The total interest on both schemes is 6640.

So, $0.44x+\frac{(14000-x) \times 2 \times 25}{100}=6640$

$x=6000$

Remaining amount invested in Scheme B = 14000-x = 14000-6000= 8000

Hence the amount invested in Scheme B is Rs.8000

# Learn More :

Ajay invested certain amount in two different schemes A and B. Scheme A offers S.I. at 12% p.a. and scheme B offer C.I. at 10% p.a. Interest accrued on the amount invested in scheme A in 2 years was Rs. 3600 and the total amount invested was Rs. 35,000. What was the interest accrued on the amount invested in scheme B for 2 years?

(a) Rs. 4200

(b) Rs. 4400

(c) Rs. 4300

(d) Rs. 4100

(e) None of these

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