Question

Satish is 25% less efficient than Abhishek Bhavya is 100% more efficiant than Satish if Satish Bhavya together can complete the work in 20/3 days find in how many days Bhavya and Abhishek together can complete the work

Answer 1

Let days taken by Abhishek to complete work alone be x

So, days taken by Satish to complete work alone = 1.25x

And, days taken by Bhavya to complete work alone = 1.25/2 x = 0.625x

In 1 day, Satish and Bhavya will complete = 1 / 1.25x + 1 / 0.625x

They complete a work in 20/3 days, so

In 1 day they will do 3/20 work

Equating the values we get

1 / 1.25x + 1 / 0.625x = 3/20

1 / 1.25x + 2 / 1.25x = 3/20

3 / 1.25x = 3/20

1.25x = 20

x = 20/1.25

x = 16 days

So, Abhishek completes in 16 days

And, Bhavya completes in 0.625(16) = 10 days
Together they will do in 1 day = 1/16 + 1/10

5/80 + 8/80 = 13/80

Therefore they will together complete the work in 80/13 days.