Question

satpal walks 2/3 km from a place p, towards east and then from there 12/7 km towards west. where will he be now from p?? ​

Answer 1

Answer:

22/21 km to the west of place p

Step-by-step explanation:

2/3 km towards the east and then 12/7 km towards the west which is in the opposite direction in a straight line.

So by taking LCM,

⇒ x = 2/3 - 12/7

      = (14 - 36)/21

      = -22/21

The minus sign indicates that Satpal is to the west of place p.

Therefore, Satpal is 22/21 km west of place p.

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Answer 2

Given: Satpal walks 2/3 km from a place p towards east and then, from there 12/7 km towards west.

To find: Satpal's position from p.

Solution:

• East and west are two opposite directions.
• So, Satpal walks towards the east and then, walks back towards the west by covering the distance travelled earlier plus some more distance towards the west.
• To find his position with respect to p, the two distances travelled must be subtracted.
• Two fractions are subtracted by making the denominators equal using L.C.M..

        $\frac{12}{7} - \frac{2}{3} = \frac{36-14}{21}$

                   $= \frac{12}{21}$

                   $= \frac{4}{7}$

Therefore, Satpal's position from p is 4/7 km.