. Saturated, unsaturated and supersaturated solutions different between in table
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Solution: By eliminating the row and column of an element, the determinant of remaining elements is the minor of the element, i.e. M i × j {{M}_{i\times j}} Mi×j and by using formula ( − 1 ) i + j M i × j {{\left( -1 \right)}^{i+j}}{{M}_{i\times j}} (−1)i+jMi×j we will get the cofactor of the element.
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Answer: A saturated solution contains the maximum amount of solute that will dissolve at that temperature. ... A supersaturated solution contains more than the maximum amount of solute that can be dissolved at that temperature.
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